請問PHP7連不到MySQL

hkw163 wrote:
資料庫是不是提早下...(恕刪)

阿德Sky wrote:
我在網路上有找到PHP7...(恕刪)

nights wrote:
mysqli_close...(恕刪)

EthanTs wrote:
有抓到資料也印出來...(恕刪)

紫色雙魚 wrote:
謝謝你詳細的程式,
我試著改過之後,
資料庫依舊連不上...
...(恕刪)

紫色雙魚 wrote:
謝謝你詳細的程式,...(恕刪)

<?php
$db_db_name = "資料庫名子";
$db_host = "網域";
$db_id = "帳號";
$db_pw = "密碼";

$db_link = mysqli_connect($db_host,$db_id,$db_pw);
$db_open_sql=mysqli_select_db($db_link,$db_db_name);

mysqli_query($db_link,"SET NAMES 'UTF8'");

$sql_query = "SELECT `orderid`, `phone`, `name` FROM `orders` WHERE `finish`=0 ORDER BY `orderid` DESC";
$result = mysqli_query($db_link, $sql_query);
$row = mysqli_fetch_row($result);

$numrow = mysqli_num_rows($result);

while($row_result[$i] = mysqli_fetch_array($result, MYSQL_ASSOC)){
$i++;
}

mysqli_close($db_link);
?>

＜html＞
＜div data-role="content"＞
＜ul data-role="listview" data-inset="true" id="listOrder" data-filter="true" data-filter-placeholder="輸入訂單號碼、電話或姓名"＞
＜?php for($i=0; $i<$numrow; $i++) { ?＞
＜li＞＜a href='showorder.php?order=＜?php echo $row_result[$i]["orderid"]; ?＞' data-ajax='false'＞
＜?php echo $row_result[$i]["orderid"]; ?＞　　
＜?php echo $row_result[$i]["phone"]; ?＞　　
＜?php echo $row_result[$i]["name"]; ?＞
＜/a＞＜/li＞
＜?php } ?＞
＜/ul＞
＜/div＞
＜/html＞